document.write( "Question 622204: $\"x%5E2%283x%5E2%2B13x-10%29%2Bx%283x%5E2%2B13x-10%29-2%283x%5E2%2B13x-10%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( "can anyone help me factor this? with step by step explanation? thanks! \n" ); document.write( "

Algebra.Com's Answer #391179 by matineesuxxx(27) $\"\"$ $\"About$

You can put this solution on YOUR website!
now first thing you need to notice with this function, $\"x%5E2%283x%5E2%2B13x-10%29%2Bx%283x%5E2%2B13x-10%29-2%283x%5E2%2B13x-10%29=0\"$ is that $\"3x%5E2%2B13x-10\"$ is a common factor so you get $\"%283x%5E2%2B13x-10%29%28x%5E2%2Bx-2%29\"$ now to factor the first quadratic equation, multiply a by c so it is $\"3%2A-10\"$ now what two numbers multiply together to give you -30 yet add together to give you a sum of 13. in this case we use +15 and -2 and we get $\"%283x%5E2%2B15x%29%2B%28-2x-10%29=0\"$ you can factor out a 3x from the first bracket and a -2 from the second giving you $\"3x%5E2%28x%2B5%29-2%28x%2B5%29\"$ and now $\"%28x%2B5%29\"$ is a common factor giving us a result of $\"%283x-2%29%28x%2B5%29\"$ \r
\n" ); document.write( "\n" ); document.write( "now for the second part. \r
\n" ); document.write( "\n" ); document.write( "we have $\"%28x%5E2%2Bx-2%29\"$ this factors easily enough into $\"%28x%2B2%29%28x-1%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "so our factored form is $\"%283x-2%29%28x%2B5%29%28x%2B2%29%28x-1%29\"$ \n" ); document.write( "

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