document.write( "Question 622170: Tickets sold in advance for a play cost $3 each. Tickets sold at the door for the same play cost $5 each. If 100 tickets were sold for this play for a total of $460, how many were purchased at the door? \n" ); document.write( "
Algebra.Com's Answer #391158 by matineesuxxx(27)\"\" \"About 
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Let x represent tickets sold at the door
\n" ); document.write( "Let y represent tickets sold in advance
\n" ); document.write( "therefore,
\n" ); document.write( "5x + 3y = 460 ( this is the statement for total amount of money)\r
\n" ); document.write( "\n" ); document.write( "x + y = 100 ( this is the statement for number of tickets sold)\r
\n" ); document.write( "\n" ); document.write( "now use either equation to solve for y, it just happens that x + y = 100 is the easiest to do this with,
\n" ); document.write( "this gives use the answer, \r
\n" ); document.write( "\n" ); document.write( "y = 100 - x\r
\n" ); document.write( "\n" ); document.write( "now plug this into our money equation and you get, \r
\n" ); document.write( "\n" ); document.write( "5x + 3(100-x) = 460\r
\n" ); document.write( "\n" ); document.write( " now simplify,\r
\n" ); document.write( "\n" ); document.write( "5x + 300 - 3x = 460
\n" ); document.write( "2x = 160
\n" ); document.write( "x = 80\r
\n" ); document.write( "\n" ); document.write( "Therefore, 80 tickets were sold at the door.
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