document.write( "Question 622140: 2+p=2p+1 \n" ); document.write( "
Algebra.Com's Answer #391145 by jim_thompson5910(35256)\"\" \"About 
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\"2%2Bp=2p%2B1\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"p=2p%2B1-2\" Subtract \"2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"p-2p=1-2\" Subtract \"2p\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-p=1-2\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-p=-1\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"p=%28-1%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate \"p\".\r
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\n" ); document.write( "\n" ); document.write( "\"p=1\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"p=1\"
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