document.write( "Question 622065: Could someone please help me? \r
\n" ); document.write( "\n" ); document.write( "Answer the following:
\n" ); document.write( "(A) Find the binomial probability P(x = 6), where n = 15 and p = 0.70.
\n" ); document.write( "(B) Set up, without solving, the binomial probability P(x is at most 6) using probability notation.
\n" ); document.write( "(C) How would you find the normal approximation to the binomial probability P(x = 6) in part A? Please show how you would calculate ľ and σ in the formula for the normal approximation to the binomial, and show the final formula you would use without going through all the calculations.\r
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Algebra.Com's Answer #391129 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P = nCx*  where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p = .70 & q = .30  and n = 15
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document.write( "nCx = 
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document.write( " P(x = 6) = 21C6(.7)^6(.3)^9 = 5005(.7)^6(.3)^9 = .012
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document.write( " P(x ≤ 6) =  P(0) + P(1) + P(2) + P(3) + P(4) + P(5) +  P(6) 
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document.write( "         = (.7)^0(.3)^15 + 2(.7)^1(.3)^14 + 105(.7)^2(.3)^13 + 455(.7)^3(.3)^12 + 1365(.7)^4(.3)^11 + 3003(.7)^5(.3)^10+ 5005(.7)^6(.3)^9
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document.write( " (c) =  and  
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document.write( "  z =  \n" );
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