document.write( "Question 622066: I don't get how I should start solving this...\r
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\n" ); document.write( "\n" ); document.write( "If the random variable z is the standard normal score and P(z > a) > 0.5, then a > 0. Why or why not?
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Algebra.Com's Answer #391121 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "If the random variable z is the standard normal score and P(z > a) > 0.5, then a > 0.
\n" ); document.write( "Note: when z > 0, then P(z) > .50 (Area under the standard normal curve to the \"left\" of the z- value >50%
\n" ); document.write( " P(z > a) > .50, then a < 0, so as the Area to the right would be > .50\r
\n" ); document.write( "\n" ); document.write( "Here is the standard normal curve. z=values of 0,±1, ±2,±3 shown
\n" ); document.write( "for ex: 50% of the area under the normal curve is to the left and right of z=0
\n" ); document.write( "one standard deviation from the mean(z= ±1) accounts for about 68.2% of the set
\n" ); document.write( "two standard deviations from the mean(z= ±2) account for about 95.4%
\n" ); document.write( "and three standard deviations from the mean(z= ±2) account for about 99.7%.\r
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