document.write( "Question 57369: One number is 5 times another. If the sum of their reciprocal is 6/35, find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #39112 by Earlsdon(6294)\"\" \"About 
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Let the two numbers be a and b.\r
\n" ); document.write( "\n" ); document.write( "a = 5b One number is 5 times another.\r
\n" ); document.write( "\n" ); document.write( "\"1%2Fa+%2B+1%2Fb+=+6%2F35\" The sum of their reciprocals is \"6%2F35\" Simplifying this:
\n" ); document.write( "\"%28a%2Bb%29%2Fab+=+6%2F35\" Cross-multiply.
\n" ); document.write( "\"35a+%2B+35b+=+6ab\" Substitute a = 5b.
\n" ); document.write( "\"175b+%2B+35b+=+30b%5E2\" Simplify.
\n" ); document.write( "\"210b+=+30b%5E2\"
\n" ); document.write( "\"30b%5E2+-+210b+=+0\" Factor out a b.
\n" ); document.write( "\"b%2830b+-+210%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"b+=+0\" and/or \"30b+-+210+=+0\"
\n" ); document.write( "\"b+=+0\" Discard this solution as not meaningful.
\n" ); document.write( "\"30b+-+210+=+0\" Add 210 to both sides.
\n" ); document.write( "\"30b+=+210\" Divide both sides by 30.
\n" ); document.write( "\"b+=+7\"
\n" ); document.write( "\"a+=+5b\"
\n" ); document.write( "\"a+=+35\"\r
\n" ); document.write( "\n" ); document.write( "The two numbers are:
\n" ); document.write( "7 and 35\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"1%2F7+%2B+1%2F35+=+5%2F35+%2B+1%2F35\" = \"6%2F35\"
\n" ); document.write( "\"35+=+5%287%29\"
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