document.write( "Question 622116: I have to solve this equation with radicals and I am not sure if i just square both sides and then that removes the radicals and it becomes a normal equation. I think that's how to do it but for some reason I think there might be a different rule for when two radicals are on two sides of the equations. If you could help me with this and show work I would really appreciate it, this has me stumped.\r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%285x-3%29=sqrt%289x-7%29\"$ \n" ); document.write( "

Algebra.Com's Answer #391118 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
square both sides and the radicals go away. In this case, it is a simple thing to do\r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%285x-3%29+=+sqrt%289x-7%29\"$ now square both sides
\n" ); document.write( " $\"%28sqrt%285x-3%29%29%5E2+=+%28sqrt%289x-7%29%29%5E2\"$
\n" ); document.write( " $\"5x-3+=+9x+-7\"$
\n" ); document.write( " $\"4+=+4x\"$
\n" ); document.write( " $\"1+=+x\"$
\n" ); document.write( "check your answers by solving the original equations with x = 1 to see if both sides resolve to the same value \n" ); document.write( "

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