document.write( "Question 622018: please help me solve for all:\r
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Algebra.Com's Answer #391109 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
2cos^2x-cosx=1\r
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\n" ); document.write( "\n" ); document.write( "2cos^2x-cosx=1\r
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\n" ); document.write( "\n" ); document.write( "2cos^2x-cosx-1=0\r
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\n" ); document.write( "\n" ); document.write( "2z^2-z-1=0 .... Let z = cosx\r
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\n" ); document.write( "\n" ); document.write( "2z^2-2z+z-1=0\r
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\n" ); document.write( "\n" ); document.write( "(2z^2-2z)+(z-1)=0\r
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\n" ); document.write( "\n" ); document.write( "2z(z-1)+(z-1)=0\r
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\n" ); document.write( "\n" ); document.write( "2z(z-1)+1(z-1)=0\r
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\n" ); document.write( "\n" ); document.write( "(2z+1)(z-1)=0\r
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\n" ); document.write( "\n" ); document.write( "(2z+1)(z-1)=0\r
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\n" ); document.write( "\n" ); document.write( "2z+1=0 or z-1=0\r
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\n" ); document.write( "\n" ); document.write( "z=-1/2 or z=1\r
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\n" ); document.write( "\n" ); document.write( "cosx=-1/2 or cosx=1\r
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\n" ); document.write( "\n" ); document.write( "x=arccos(-1/2) or x=arccos(1)\r
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\n" ); document.write( "\n" ); document.write( "x=arccos(-1/2)\r
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\n" ); document.write( "\n" ); document.write( "x=2pi/3+2pi*n or x = 4pi/3 + 2pi*n\r
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\n" ); document.write( "\n" ); document.write( "x=arccos(1)\r
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\n" ); document.write( "\n" ); document.write( "x=2pi*n\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are:\r
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\n" ); document.write( "\n" ); document.write( "x=2pi/3+2pi*n, x = 4pi/3 + 2pi*n, or x=2pi*n
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