document.write( "Question 621901: Factor by grouping, if possible, and show me how to check... much appreciated
\n" ); document.write( "8a^3 - 2a^2 + 12a – 3
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Algebra.Com's Answer #391031 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"8a%5E3-2a%5E2%2B12a-3\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%288a%5E3-2a%5E2%29%2B%2812a-3%29\" Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( "\"2a%5E2%284a-1%29%2B3%284a-1%29\" Factor out the GCF \"2a%5E2\" out of the first group. Factor out the GCF \"3\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%282a%5E2%2B3%29%284a-1%29\" Since we have the common term \"4a-1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"8a%5E3-2a%5E2%2B12a-3\" factors to \"%282a%5E2%2B3%29%284a-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"8a%5E3-2a%5E2%2B12a-3=%282a%5E2%2B3%29%284a-1%29\"
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