document.write( "Question 621624: A chord 16cm long is perpendicular to the radius of a circle. The distance of the intersection of the chord and the radius to the outer end of the radius is 2cm. What is the radius of the circle?
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Algebra.Com's Answer #390982 by ankor@dixie-net.com(22740)\"\" \"About 
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A chord 16cm long is perpendicular to the radius of a circle.
\n" ); document.write( "The distance of the intersection of the chord and the radius to the outer end of the radius is 2cm.
\n" ); document.write( "What is the radius
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\n" ); document.write( "Draw this out
\n" ); document.write( "let x = the distance from center to the intersection of the radius thru the chord
\n" ); document.write( "then the radius: r = x+2
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\n" ); document.write( "The radius is equal the hypotenuse of a right triangle with legs of 8 and x
\n" ); document.write( "r =\"sqrt%288%5E2%2Bx%5E2%29\"
\n" ); document.write( "We also know that r = x+2, therefore
\n" ); document.write( "x + 2 = \"sqrt%2864+%2B+x%5E2%29\"
\n" ); document.write( "Square both sides
\n" ); document.write( "(x+2)^2 = 64 + x^2
\n" ); document.write( "FOIL (x+2)(x+2)
\n" ); document.write( "x^2 + 4x + 4 = 64 + x^2
\n" ); document.write( "subtract x^2 from both sides
\n" ); document.write( "4x + 4 = 64
\n" ); document.write( "4x = 64 - 4
\n" ); document.write( "4x = 60
\n" ); document.write( "x = 60/4
\n" ); document.write( "x = 15
\n" ); document.write( "therefore
\n" ); document.write( "r = 15 + 2 = 17 cm is the radius \n" ); document.write( "
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