document.write( "Question 621749:  -1< or equal to 2x+1
| Algebra.Com's Answer #390960 by Alan3354(69443)     You can put this solution on YOUR website! -1< or equal to 2x+1 < or equal to 3 \n" ); document.write( "-1 <= 2x+1 <=3 \n" ); document.write( "Subtract 1 \n" ); document.write( "-2 <= 2x <=2 \n" ); document.write( "Divide by 2 \n" ); document.write( "-1 <= x <= 1 \n" ); document.write( " \n" ); document.write( " |