document.write( "Question 621607: please help me solve: \r
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\n" ); document.write( "\n" ); document.write( "cosx(tan^2x+1)=secx
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Algebra.Com's Answer #390957 by lwsshak3(11628)\"\" \"About 
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\n" ); document.write( "cosx(tan^2x+1)=secx
\n" ); document.write( "start with left side
\n" ); document.write( "cosx[(sin^2x/cos^2x)+1]
\n" ); document.write( "=cosx(cos^2x+sin^2x)/cos^2x
\n" ); document.write( "=cosx(1)/cos^2x
\n" ); document.write( "1/cosx=secx
\n" ); document.write( "verified:
\n" ); document.write( "left side=right side
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