document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=621739>Question 621739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If angle A is acute and tan A=2/3, then...\r<BR>\n" );
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document.write( "The answer is cot(90degrees-A)=2/3 \r<BR>\n" );
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document.write( "I dont understand how to arrive at this answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390951 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If angle A is acute and tan A=2/3, then... <BR>\n" );
document.write( "The answer is cot(90degrees-A)=2/3 <BR>\n" );
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document.write( "The answer is based on the fact that tan and cot being reciprocal functions, the tan of an angle is equal to the cot of its complement like in given problem.<BR>\n" );
document.write( "complement of A=90º-A.<BR>\n" );
document.write( "Example: Tan 30º=cot(90-30)=cot 60º=1/&#8730;3=&#8730;3/3 </SPAN>\n" );
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