document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=621761>Question 621761</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I would like some help with this problem:<BR>\n" );
document.write( "Two cards are drawn without replacement from a standard deck of cards.Find the following probabilities:\r<BR>\n" );
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document.write( "a) both cards are diamonds\r<BR>\n" );
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document.write( "b) the second is a club, given that the first is a club\r<BR>\n" );
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document.write( "c) the second card is a 9, given that the first card was a 3\r<BR>\n" );
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document.write( "Thank you for your help!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390939 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "a) The probability of drawing a diamond on the first draw is 13/52 or 1/4.  But on the second draw, given that the first was a diamond, the probability is 12/51.  These are two independent events so the total probability is the product of the two individual probabilities.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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