document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=621625>Question 621625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A dairy needs 246 gallons of milk containing 5% butterfat. How many gallons each of milk containing 6% butterfat and milk containing 3% butterfat must be used to obtain the desired 246 gallons? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390921 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390921\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of gal of 6% butterfat needed<BR>\n" );
document.write( "Then 246-x=number of gal of 3% butterfat needed\r<BR>\n" );
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document.write( "Now we know that the amount of pure butterfat in the 6% mixture (0.06x) plus the amount of pure butterfat in the 3% mixture(0.03(246-x)) has to equal the amount of pure butterfat in the final mixture(0.05*246), soooooo:<BR>\n" );
document.write( "0.06x+0.03(246-x)=0.05*246 simplify<BR>\n" );
document.write( "0.06x+7.38-0.03x=12.3<BR>\n" );
document.write( "0.03x=12.3-7.38<BR>\n" );
document.write( "0.03x=4.92<BR>\n" );
document.write( "x=164 gal------amount of 6% butterfat needed<BR>\n" );
document.write( "246-164=82----amount of 3% butterfat needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "164*0.06+82*0.03=0.05*246<BR>\n" );
document.write( "9.84+2.46=12.3<BR>\n" );
document.write( "12.3=12.3\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
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