document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=621634>Question 621634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the point in x-axis whose distance from the point (1,2) is root under 13\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390837 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Make a coordinate grid and plot the point (1,2).<BR>\n" );
document.write( "Now draw a vertical line from (1,2) down to (1,0). That segment is of length 2 (the distance between (1,2) and (1,0)) and is one leg of a right triangle. <BR>\n" );
document.write( "We want to find a point on the x axis that will include the drawn segment and result in a right triangle with hypotenuse of length <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2813%29 ALIGN=MIDDLE  ALT=\"sqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "There are two points that are solutions. One point is to the left of (1,0) and the other is an equal distance to the right of (1,0). <BR>\n" );
document.write( "So how far is that distance?<BR>\n" );
document.write( "Use the Pythagorean theorem.<BR>\n" );
document.write( "You know the length of two sides of a right triangle, so you can solve for the third side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+%2B+b%5E2+=+c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2+%2B+b%5E2+=+c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E2+%2B+b%5E2+=+%28sqrt%2813%29%29%5E2 ALIGN=MIDDLE  ALT=\"2%5E2+%2B+b%5E2+=+%28sqrt%2813%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4+%2B+b%5E2+=+13 ALIGN=MIDDLE  ALT=\"4+%2B+b%5E2+=+13\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+=+13-4 ALIGN=MIDDLE  ALT=\"b%5E2+=+13-4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+=+9 ALIGN=MIDDLE  ALT=\"b%5E2+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+3 ALIGN=MIDDLE  ALT=\"b+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the points are 3 units on either side of (1,0). That means (4,0) and (-2,0)<BR>\n" );
document.write( "are the two points that are solutions. </SPAN>\n" );
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