document.write( "Question 621572: Dmitri needs 7 liters of a 24% solution of sulfuric acid for a research project in molecular biology. He has two supplies of sulfuric acid solution: one is an unlimited supply of 28% solution and the other an unlimited supply of the 14% solution. How many liters of each solution should Dmitri use? \n" ); document.write( "
Algebra.Com's Answer #390832 by dragonwalker(73)\"\" \"About 
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First look at how each solution is different from the required concentration.\r
\n" ); document.write( "\n" ); document.write( "The 28% is +4% from the required 24%
\n" ); document.write( "The 14% id -10% from the required 24%\r
\n" ); document.write( "\n" ); document.write( "So the effect of the 28% is only 4/10 of the effect of the 14% \r
\n" ); document.write( "\n" ); document.write( "so you need 10/4 times more of the 28% than the 14%\r
\n" ); document.write( "\n" ); document.write( "So let us call the volume of the 14% 'x'
\n" ); document.write( "So the volume of the 28% is10x/4\r
\n" ); document.write( "\n" ); document.write( "As the total volume needed is 7 liters this may be written:\r
\n" ); document.write( "\n" ); document.write( "x + 10x/4 = 7\r
\n" ); document.write( "\n" ); document.write( "solve for x:
\n" ); document.write( "(multiply all by 4 to remove denominator of 10x/4)\r
\n" ); document.write( "\n" ); document.write( "4x + 10x = 28
\n" ); document.write( "14x = 28
\n" ); document.write( "x = 28/14
\n" ); document.write( "x = 2\r
\n" ); document.write( "\n" ); document.write( "So the volume of the 14% is 2 litres and therefore the amount of 28% is 10/4 x 2
\n" ); document.write( "=5\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "Multiply the effect of each concentration (i.e. the difference between the concentration and desired by the calculated volume needed and add together. If the desired concentration of 24% was reached the answer should be zero.\r
\n" ); document.write( "\n" ); document.write( "2 times -10 + 5 times +4 = 0
\n" ); document.write( "
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