document.write( "Question 621585: The length of a rectangle is four times its width.
\n" ); document.write( "If the perimeter of the rectangle is 50in, find its area.
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Algebra.Com's Answer #390831 by Maths68(1474)\"\" \"About 
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\n" ); document.write( "Length = l
\n" ); document.write( "Width = w
\n" ); document.write( "Perimeter = p = 50
\n" ); document.write( "Given
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\n" ); document.write( "The length of a rectangle is four times its width
\n" ); document.write( "l=4w\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of rectangle = 2(l+w)
\n" ); document.write( "50=2(4w+w)
\n" ); document.write( "50=2(5w)
\n" ); document.write( "50=10w
\n" ); document.write( "50/10=w
\n" ); document.write( "5=w
\n" ); document.write( "w=5\r
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\n" ); document.write( "\n" ); document.write( "Area of rectangle = length * width
\n" ); document.write( "a=l*w
\n" ); document.write( "a=4w*w
\n" ); document.write( "a=4w^2............(1)
\n" ); document.write( "Put the value of w in (1)
\n" ); document.write( "a=4(5)^2
\n" ); document.write( "a=4(25)
\n" ); document.write( "a=100in^2\r
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\n" ); document.write( "\n" ); document.write( "Area of rectangle is 100 square inches.
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