document.write( "Question 621585: The length of a rectangle is four times its width.
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document.write( "If the perimeter of the rectangle is 50in, find its area. \n" );
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Algebra.Com's Answer #390831 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Length = l \n" ); document.write( "Width = w \n" ); document.write( "Perimeter = p = 50 \n" ); document.write( "Given \n" ); document.write( "------ \n" ); document.write( "The length of a rectangle is four times its width \n" ); document.write( "l=4w\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter of rectangle = 2(l+w) \n" ); document.write( "50=2(4w+w) \n" ); document.write( "50=2(5w) \n" ); document.write( "50=10w \n" ); document.write( "50/10=w \n" ); document.write( "5=w \n" ); document.write( "w=5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area of rectangle = length * width \n" ); document.write( "a=l*w \n" ); document.write( "a=4w*w \n" ); document.write( "a=4w^2............(1) \n" ); document.write( "Put the value of w in (1) \n" ); document.write( "a=4(5)^2 \n" ); document.write( "a=4(25) \n" ); document.write( "a=100in^2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area of rectangle is 100 square inches. \n" ); document.write( " \n" ); document.write( " |