document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57270>Question 57270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> givin three sides of a traingle: 330, 270, 240, find the area of the largest possible circle that fits within the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39079 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> givin three sides of a traingle: 330, 270, 240, find the area of the largest possible circle that fits within the triangle<BR>\n" );
document.write( "givin three sides of a traingle: 330, 270, 240, find the area of the largest possible circle that fits within the triangle\r<BR>\n" );
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document.write( "SUCH A CIRCLE IS CALLED INCIRCLE.THERE ARE SEVERAL WAYS TO FIND IT.I DONOT KNOW ABOUT <BR>\n" );
document.write( "YOUR BACK ROUND. I AM GIVING BELOW ONE WAY USING TRIGNOMETRY - PROPERTIES OF TRIANGLES.\r<BR>\n" );
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document.write( "DEL = r*s = SQUARE ROOT OF [ s(s-a)(s-b)(s-c)]<BR>\n" );
document.write( "WHERE <BR>\n" );
document.write( "DEL = AREA OF TRIANGLE<BR>\n" );
document.write( "r = IN RADIUS<BR>\n" );
document.write( "a,b,c ARE SIDES OF TRIANGLE<BR>\n" );
document.write( "s = (a+b+c)/2 = SEMI PERIMETER OF THE TRIANGLE.<BR>\n" );
document.write( "WE HAVE <BR>\n" );
document.write( "a = 330<BR>\n" );
document.write( "b = 270<BR>\n" );
document.write( "c = 240<BR>\n" );
document.write( "s = (a+b+c)/2 = (330+270+240)/2 = 840/2 = 420<BR>\n" );
document.write( "r*420 = SQ.RT.[420(420-330)(420-270)(420-240)] = 					31946.83083<BR>\n" );
document.write( "r*420 = 31947					<BR>\n" );
document.write( "r = IN RADIUS = 31947/420 = 			76.06388095		<BR>\n" );
document.write( "AREA OF INCIRCLE = PI*r*r = 			18167.19878 </SPAN>\n" );
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