document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=621426>Question 621426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use method of substitution to solve the system of linear equations\r<BR>\n" );
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document.write( "1.  4a= 6 - b<BR>\n" );
document.write( "+6  = +6<BR>\n" );
document.write( "4a+6=b (stuck from here) \r<BR>\n" );
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document.write( " 2  4a= 5 - b  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390738 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use method of substitution to solve the system of linear equations <BR>\n" );
document.write( "1. 4a= 6 - b<BR>\n" );
document.write( "+6 = +6<BR>\n" );
document.write( "4a+6=b (stuck from here) \r<BR>\n" );
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document.write( "2 4a= 5 - b <BR>\n" );
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document.write( "If your 2 eqns are<BR>\n" );
document.write( "use method of substitution to solve the system of linear equations <BR>\n" );
document.write( "4a = 6 - b<BR>\n" );
document.write( "4a = 5 - b <BR>\n" );
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document.write( "Sub for 4a<BR>\n" );
document.write( "6 - b = 5 - b<BR>\n" );
document.write( "6 = 5<BR>\n" );
document.write( "Inconsistent, no solution.<BR>\n" );
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