document.write( "Question 621355: How many grams of an alloy that is 70% gold should be melted with 20 grams of an alloy that is 10% gold to produce an alloy that is 60% gold ? \n" ); document.write( "
Algebra.Com's Answer #390699 by jsmallt9(3758)\"\" \"About 
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\n" ); document.write( "x*0.70 + 20*0.10 = (x+20)*0.60

\n" ); document.write( "Now we use algebra to solve it. First we simplify each side:
\n" ); document.write( "0.70x + 2 = 0.60x + 12
\n" ); document.write( "Subtract 0.60x from each side:
\n" ); document.write( "0.10x + 2 = 12
\n" ); document.write( "Subtracting 2:
\n" ); document.write( "0.10x = 10
\n" ); document.write( "Dividing both sides by 0.10:
\n" ); document.write( "x = 100

\n" ); document.write( "So we mix 100 grams of the 70% gold with the 20 grams of the 10% gold to get 100+20 or 120 grams of 60% gold.
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