document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57346>Question 57346</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, Could you help me on the solution to this question,\r<BR>\n" );
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document.write( "The sum of a series is given by the formula Sn=(4^n)(n-3). Determine the value of the 6th term.\r<BR>\n" );
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document.write( "Thanks all!. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39069 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of a series is given by the formula Sn=(4^n)(n-3). Determine the value of the 6th term.<BR>\n" );
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document.write( "The 6th term = the sum of 6 terms - the sum of 5 terms.<BR>\n" );
document.write( "6th term = (4^6)(6-3) - 4^5(5-3)<BR>\n" );
document.write( "=4^5(4(3)-(5-3))<BR>\n" );
document.write( "=1024(10)<BR>\n" );
document.write( "=10240<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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