document.write( "Question 621276: Printing Press A starts working on a job at 8:00 am. Working alone, press A would take 24 hours to do the job. At 9:30 am, press B also begins to run the same job as A. Press B is twice as fast as press A. What time will the job be completed? \n" ); document.write( "
Algebra.Com's Answer #390672 by josmiceli(19441)\"\" \"About 
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How much of the job did press A get done in 1.5 hrs
\n" ); document.write( "from 8 AM to 9:30 AM?
\n" ); document.write( "A's rate is ( 1 job ) / ( 24 hrs )
\n" ); document.write( "In 1.5 hrs:
\n" ); document.write( "\"+%281%2F24%29%2A1.5+=+.0625+\" job/hr
\n" ); document.write( "Now both A and B work on job
\n" ); document.write( "There is \"+1+-+.0625+=+.9375+\"
\n" ); document.write( "of the job left to do.
\n" ); document.write( "B's rate is ( 1 job ) / ( 12 hrs )
\n" ); document.write( "\"+1%2F24+%2B+1%2F12++=+.9375+%2F+t+\"
\n" ); document.write( "Multiply both sides by \"+24t+\"
\n" ); document.write( "\"+t+%2B+2t+=+22.5+\"
\n" ); document.write( "\"+3t+=+22.5+\"
\n" ); document.write( "\"+t+=+7.5+\"
\n" ); document.write( "In 7.5 hrs after B starts, the job is done
\n" ); document.write( "9:30 + 7.5 = 5 PM job is done
\n" ); document.write( "check answer:
\n" ); document.write( "\"+1%2F24+%2B+1%2F12++=+.9375+%2F+t+\"
\n" ); document.write( "\"+1%2F24+%2B+1%2F12++=+.9375+%2F+7.5+\"
\n" ); document.write( "\"+1%2F24+%2B+2%2F24+=+.125+\"
\n" ); document.write( "\"+1%2F8+=+.125+\"
\n" ); document.write( "\"+.125+=+.125+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );