document.write( "Question 621276: Printing Press A starts working on a job at 8:00 am. Working alone, press A would take 24 hours to do the job. At 9:30 am, press B also begins to run the same job as A. Press B is twice as fast as press A. What time will the job be completed? \n" ); document.write( "
Algebra.Com's Answer #390672 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! How much of the job did press A get done in 1.5 hrs \n" ); document.write( "from 8 AM to 9:30 AM? \n" ); document.write( "A's rate is ( 1 job ) / ( 24 hrs ) \n" ); document.write( "In 1.5 hrs: \n" ); document.write( " \n" ); document.write( "Now both A and B work on job \n" ); document.write( "There is \n" ); document.write( "of the job left to do. \n" ); document.write( "B's rate is ( 1 job ) / ( 12 hrs ) \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In 7.5 hrs after B starts, the job is done \n" ); document.write( "9:30 + 7.5 = 5 PM job is done \n" ); document.write( "check answer: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |