document.write( "Question 621310: Okay. So we were given homework for summer. But there's one big problem. I don't remember learning this. And I've looked everywhere to find help on how to solve it. So if you could explain the steps. That would be very appreciated. So I can use it as a model when solving other problems like it. Thank you=)\r
\n" ); document.write( "\n" ); document.write( "27^(x+1) = 9^(2x-4)
\n" ); document.write( "The exponents are (x+1) and (2x-4)
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Algebra.Com's Answer #390668 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"27%5E%28%28x%2B1%29%29+=+9%5E%28%282x-4%29%29\"
\n" ); document.write( "note that 27 = 3^3 and 9 = 3^2, so we can rewrite this to
\n" ); document.write( "\"3%5E%283%28x%2B1%29%29+=+3%5E%282%282x-4%29%29\"
\n" ); document.write( "If the bases are equal, the exponents are equal, so we have
\n" ); document.write( "3(x+1) = 2(2x-4)
\n" ); document.write( ":
\n" ); document.write( "3x + 3 = 4x - 8
\n" ); document.write( "3 + 8 = 4x - 3x
\n" ); document.write( "11 = x
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\n" ); document.write( ":
\n" ); document.write( "Check this on your calc, (replace x with 11)
\n" ); document.write( "27^12 = 1.5(10^17)
\n" ); document.write( "9^18 = 1/5(10.17)
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