document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=621267>Question 621267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve these questions?  I know how I have to use the geometric sequence, but I'm stumped.  The question is, \"True or False, are these equal?\"\r<BR>\n" );
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document.write( "1000<BR>\n" );
document.write( " &#931;      7 (3/4)^n<BR>\n" );
document.write( "n=2\r<BR>\n" );
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document.write( "         998<BR>\n" );
document.write( "63/16  &#931;      (3/4)^n<BR>\n" );
document.write( "         n=0 <BR>\n" );
document.write( "(I cannot get my computer to edit this question correctly.  Just to clarify:  The 63/16 is in front of the sigma sign.  The 998 is above sigma and n=0 below. The (3/4)^n is to the right)\r<BR>\n" );
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document.write( "THANK YOU, THANK YOU, THANK YOU!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390652 by </B><A HREF=/tutors/aboutme.mpl?userid=Emsley><B>Emsley(35)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Emsley><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390652\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First series  1st term=63/16 Common ratio=3/4 No of terms=999<BR>\n" );
document.write( "So sum=63/16(1-3/4^999)/1-3/4=63/4(1-3/4^999)<BR>\n" );
document.write( "Second series 1st term=1 Common ratio=3/4 No of terms=999\r<BR>\n" );
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document.write( "sum=63S/16*1(1-3/4^999)/(1-3/4)=63/16(1-3/4^999) So TRUE </SPAN>\n" );
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