document.write( "Question 619584: Hi, please help me solve the question: \r
\n" ); document.write( "\n" ); document.write( "A rectangular sheet of steel is twice a long as it is wide. From each corner a 2 cm-square is cut. Then the sides are folded to make a box (without top), which holds 60 cubic centimeters. What were the original dimensions of the steel sheet?\r
\n" ); document.write( "\n" ); document.write( "Thank you! \n" ); document.write( "
Algebra.Com's Answer #390641 by lwsshak3(11628)\"\" \"About 
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A rectangular sheet of steel is twice a long as it is wide. From each corner a 2 cm-square is cut. Then the sides are folded to make a box (without top), which holds 60 cubic centimeters. What were the original dimensions of the steel sheet?
\n" ); document.write( "**
\n" ); document.write( "let x=width of original steel sheet
\n" ); document.write( "2x=length of original steel sheet
\n" ); document.write( "After making a 2 cm square cut at each corner and folding the sides, you end up with a box of the following dimensions:
\n" ); document.write( "width=x-4
\n" ); document.write( "length=2x-4
\n" ); document.write( "height=2
\n" ); document.write( "volume=length*width*height=60 m^3
\n" ); document.write( "2(x-4)(2x-4)=60
\n" ); document.write( "(x-4)(2x-4)=30
\n" ); document.write( "2x^2-12x+16=30
\n" ); document.write( "2x^2-12x+14=0
\n" ); document.write( "x^2-6x-7=0
\n" ); document.write( "(x-7)(x+1)=0
\n" ); document.write( "x=-1 (reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=7
\n" ); document.write( "2x=14
\n" ); document.write( "width of original steel sheet=7 cm
\n" ); document.write( "length of original steel sheet=14 cm
\n" ); document.write( " \n" ); document.write( "
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