document.write( "Question 621199: Please help me solve this equation: A rectangular box that is closed at the top is constructed so that its length, width, and height are in the ratio 5 : 4 : 2, respectively. If the surface area of the box is 931 square centimeters, what is the number of cubic centimeters in the volume of the box? Thanks \n" ); document.write( "
Algebra.Com's Answer #390630 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular box that is closed at the top is constructed so that its length, width, and height are in the ratio 5 : 4 : 2, respectively.
\n" ); document.write( " If the surface area of the box is 931 square centimeters, what is the number of cubic centimeters in the volume of the box?
\n" ); document.write( ":
\n" ); document.write( "Let x = the multiplier
\n" ); document.write( "then
\n" ); document.write( "5x = the length
\n" ); document.write( "4x = the width
\n" ); document.write( "2x = the height
\n" ); document.write( ":
\n" ); document.write( "Surface area formula: S.A. = 2(L*W)+2(L*H)+2(W*H)
\n" ); document.write( "therefore
\n" ); document.write( "2(5x*4x) + 2(5x*2x) + 2(4x*2x) = 931
\n" ); document.write( "2(20x^2) + 2(10x^2) + 2(8x^2) = 931
\n" ); document.write( "40x^2 + 20x^2 + 16x^2 = 931
\n" ); document.write( "76x^2 = 931
\n" ); document.write( "x^2 = 931/76
\n" ); document.write( "x^2 = 12.25
\n" ); document.write( "x = \"sqrt%2812.25%29\"
\n" ); document.write( "x = 3.5 is the multiplier
\n" ); document.write( "hence
\n" ); document.write( "5*3.5 = 17.5 is the length
\n" ); document.write( "4*3.5 = 14.0 is the width
\n" ); document.write( "2*3.5 = 7.0 is the height
\n" ); document.write( ":
\n" ); document.write( "Find the volume
\n" ); document.write( "V = 17.5 * 14 * 7
\n" ); document.write( "V = 1715 cu/cm is the volume
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