document.write( "Question 621180: Find the equation for the line that passes through the point (3,5), and that is parallel to the line with the equation (y-1=-2/3(x-1).\r
\n" ); document.write( "\n" ); document.write( "Note: -2/3 is suppose to be in fraction form, so it's -2 OVER 3. NOT DIVIDED\r
\n" ); document.write( "\n" ); document.write( "thanks, \n" ); document.write( "
Algebra.Com's Answer #390623 by nerdybill(7384)\"\" \"About 
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Find the equation for the line that passes through the point (3,5), and that is parallel to the line with the equation (y-1=-2/3(x-1).
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\n" ); document.write( "Note: a fraction (a/b) can be considered as \"a divided by b\".
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\n" ); document.write( "Slope of:
\n" ); document.write( "y-1=-2/3(x-1)
\n" ); document.write( "is -2/3
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\n" ); document.write( "A line parallel will have the same slope.
\n" ); document.write( "So, now we have:
\n" ); document.write( "m (slope) is -2/3
\n" ); document.write( "and one point (3,5)
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\n" ); document.write( "Plug into \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x -x1)
\n" ); document.write( "y - 5 = (-2/3)(x - 3)
\n" ); document.write( "y - 5 = (-2/3)x - (-2/3)3
\n" ); document.write( "y - 5 = (-2/3)x - (-2)
\n" ); document.write( "y - 5 = (-2/3)x + 2
\n" ); document.write( "y = (-2/3)x + 7 (this is what they're looking for in \"slope-intercept\" form)\r
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