document.write( "Question 621158: Solve for θ in the equation tan θ = 2.42 when 180º < θ < 360º. Round your answer to the nearest tenth of a degree. \n" ); document.write( "
Algebra.Com's Answer #390599 by Edwin McCravy(20060)\"\" \"About 
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document.write( "Solve for θ in the equation tan θ = 2.42 when 180° < θ < 360°.\r\n" );
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document.write( "180° < θ < 360° consists of quadrants III and\r\n" );
document.write( "IV. \r\n" );
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document.write( "Observing tan θ = 2.42, noticing that 2.47 is a positive number and\r\n" );
document.write( "realizing that the tangent is only positive in quadrant III, we know that\r\n" );
document.write( "θ is an angle in quadrant III, so \r\n" );
document.write( "180° < θ < 270°\r\n" );
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document.write( "So we use the inverse tangent feature to get 67.54845354°.  But that is NOT \r\n" );
document.write( "the answer because 67.54845354° is an angle in quadrant I, not quadrant III.\r\n" );
document.write( "The value 67.54845354° tells how many degrees θ swings into quadrant III.\r\n" );
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document.write( "So we must add 67.54845354° + 180° and get 247.5484535°.\r\n" );
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document.write( "In the drawing above, the green arc represents the 67.54845354°, which\r\n" );
document.write( "is the reference angle, and the red arc represents the 247.5484535°. \r\n" );
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document.write( "Edwin
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