document.write( "Question 621132: If a car had increased its average speed for a 210 mile journey by 5 MPH the journey would have been completed in one hour less. What was the original speed of the car for the journey? \n" ); document.write( "
Algebra.Com's Answer #390598 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If a car had increased its average speed for a 210 mile journey by 5 MPH the journey would have been completed in one hour less. \n" ); document.write( " What was the original speed of the car for the journey? \n" ); document.write( ": \n" ); document.write( "Let s = original speed \n" ); document.write( "then \n" ); document.write( "(s+5) = the faster speed \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "original time - faster time = 1 hr \n" ); document.write( " \n" ); document.write( "multiply equation by s(s+5); results: \n" ); document.write( "210(s+5) - 210s = 1s(s+5) \n" ); document.write( ": \n" ); document.write( "210s + 1050 - 210s = s^2 + 5s \n" ); document.write( "Arrange as a quadratic equation \n" ); document.write( "s^2 + 5s - 1050 = 0 \n" ); document.write( "You can use the quadratic equation, but this will factor \n" ); document.write( "(s-30)(s+35) = 0 \n" ); document.write( "the positive solution is all we want here \n" ); document.write( "s = 30 mph is the original speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this out; find the actual time for each speed \n" ); document.write( "210/30 = 7 hr \n" ); document.write( "210/35 = 6 hrs \n" ); document.write( "-------------- \n" ); document.write( "differ: 1 hr \n" ); document.write( " |