document.write( "Question 7103: I would appreciate it if someone would help me solve this equation:
\n" ); document.write( "sqrt3x-1/2=4
\n" ); document.write( "All of 3x-1/2 is supposed to be square rooted. So I tried squaring both sides of the equation to get rid of the square root. So I got:
\n" ); document.write( "3x-1/2=16
\n" ); document.write( "Then I cross multiplied and now I have:
\n" ); document.write( "3x-1/32
\n" ); document.write( "It's been a year since I took Algebra1, so even if I've been correct so far, I don't know where to go from here. Thank you in advance to the tutor who helps me with this. \n" ); document.write( "

Algebra.Com's Answer #3905 by prince_abubu(198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let's take it from the point where you got $\"+3x+-+1%2F2+=+16+\"$ . You don't need to do any cross-multiplying because the 2 is NOT a denominator of the entire expression on the left hand side of the equals sign. the -1/2 really is -0.5. So, your equation would be $\"+3x+-+0.5+=+16+\"$ - just like any normal linear equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So, going on further, you'll get $\"+3x+=+16.5+\"$ <---- 0.5 added to both sides. When you finally solve for x, x = 5.5. \n" ); document.write( "

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