document.write( "Question 620936: Identify the conic section. If it is a parabola, give the vertex. If it is an ellipse or hyperbola, give the center and the foci. \r
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Algebra.Com's Answer #390469 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Identify the conic section. If it is a parabola, give the vertex. If it is an ellipse or hyperbola, give the center and the foci. \n" ); document.write( "8x^2-6y^2+48x-24y+0=0 \n" ); document.write( "8x^2+48x-6y^2-24y+0=0 \n" ); document.write( "complete the square \n" ); document.write( "8(x^2+6x+9)-6(y^2+4y+4)=72-24 \n" ); document.write( "8(x+3)^2-6(y+2)^2=48 \n" ); document.write( "(x+3)^2/6-(y+2)^2/8=1 \n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis \n" ); document.write( "Its standard form: (x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center \n" ); document.write( "For given hyperbola: \n" ); document.write( "center: (-3,-2) \n" ); document.write( "a^2=6 \n" ); document.write( "b^2=8 \n" ); document.write( "c^2=a^2+b^2=6+8=14 \n" ); document.write( "c=√14≈3.7 \n" ); document.write( "foci: (-3±c,-2)=(-3±3.7,-2)=(-6.7,-2) and (0.7,-2) \n" ); document.write( " \n" ); document.write( " |