document.write( "Question 620717: please show how to solve this I am confused...\r
\n" ); document.write( "\n" ); document.write( "Altitude of a launched object. The altitude of an object, in meters, is given by the polynomial\r
\n" ); document.write( "\n" ); document.write( "h + vt − 4.9t2,\r
\n" ); document.write( "\n" ); document.write( "where h is the height, in meters, at which the launch occurs, v is the initial upward speed (or velocity), in meters per second, and t is the number of seconds for which the object is airborne\r
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Algebra.Com's Answer #390353 by lwsshak3(11628) $\"\"$ $\"About$

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Altitude of a launched object. The altitude of an object, in meters, is given by the polynomial
\n" ); document.write( "h + vt − 4.9t2,
\n" ); document.write( "where h is the height, in meters, at which the launch occurs, v is the initial upward speed (or velocity), in meters per second, and t is the number of seconds for which the object is airborne
\n" ); document.write( "**
\n" ); document.write( "rewrite equation:
\n" ); document.write( "-4.9t^2+vt+h
\n" ); document.write( "You should see this is an equation of a parabola that opens downwards. (has a maximum)
\n" ); document.write( "Its standard form: y=-A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex.
\n" ); document.write( "To change given equation to this form, you must complete the square, from which you can see the coordinates of the vertex.
\n" ); document.write( "Given equation gives the height(m) of the airborne object at any time t(sec)
\n" ); document.write( "h(t)=-4.9t^2+vt+h \n" ); document.write( "

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