document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620690>Question 620690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Darla is building a new desk. To make sure she had made a square corner, she measures 6ft. from the corner along one edge and 3ft. from the corner along the other edge. How long should the diagonal be between those two points if the corner is a right angle?\r<BR>\n" );
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document.write( "Diagonal = ? ft.<BR>\n" );
document.write( "(Round to the nearest thousandth) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390335 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D = sqrt( L^2 + W^2 )\r<BR>\n" );
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document.write( "D = sqrt( 6^2 + 3^2 )\r<BR>\n" );
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document.write( "D = sqrt( 36 + 9 )\r<BR>\n" );
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document.write( "D = sqrt( 45 )\r<BR>\n" );
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document.write( "D = 6.7082\r<BR>\n" );
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document.write( "D = 6.708\r<BR>\n" );
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document.write( "So the diagonal should be roughly <font color=\"red\">6.708 feet</font> </SPAN>\n" );
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