document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620679>Question 620679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Its Telling me to solve this equation. i dont understand how to work this problem out i know i have to get a on one side to find out what it represents but i tried and dont get no where .\r<BR>\n" );
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document.write( "(5/4)(2a-10)=(-3/4a)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390329 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (5/4)(2a-10)=(-3/4a)<BR>\n" );
document.write( "Maybe you mean<BR>\n" );
document.write( "(5/4)(2a-10)=(-3/4)a<BR>\n" );
document.write( "Multiply by 4<BR>\n" );
document.write( "5(2a-10) = -3a<BR>\n" );
document.write( "Expand<BR>\n" );
document.write( "10a - 50 = -3a<BR>\n" );
document.write( "Add 50<BR>\n" );
document.write( "10a = -3a + 50<BR>\n" );
document.write( "Add 3a<BR>\n" );
document.write( "13a = 50<BR>\n" );
document.write( "Divide by 13<BR>\n" );
document.write( "a = 50/13<BR>\n" );
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