document.write( "Question 620614: Beth's mom is 6 times older than Beth. Beth's dad is 7 years older than Beth's mom. The sum of their ages is 72. How old are each of them? \n" ); document.write( "

Algebra.Com's Answer #390328 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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let b = Beth's age
\n" ); document.write( "let m = Mom's age
\n" ); document.write( "let d = Dad's age
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement. Arrange to get b and d in terms of m:
\n" ); document.write( ";
\n" ); document.write( "\"Beth's mom is 6 times older than Beth.\"
\n" ); document.write( "m = 6b
\n" ); document.write( "or
\n" ); document.write( "b = $\"1%2F6\"$ m
\n" ); document.write( ":
\n" ); document.write( "\"Beth's dad is 7 years older than Beth's mom.\"
\n" ); document.write( "d = m + 7\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( "\"The sum of their ages is 72.\"
\n" ); document.write( "b + m + d = 72
\n" ); document.write( "Replace b and d
\n" ); document.write( "( $\"1%2F6\"$ m) + m + (m+7) = 72
\n" ); document.write( "( $\"1%2F6\"$ m) + 2m = 72 - 7
\n" ); document.write( "( $\"1%2F6\"$ m) + 2m = 65
\n" ); document.write( "multiply equation by 6, results
\n" ); document.write( "m + 6(2m) = 6(65)
\n" ); document.write( "13m = 390
\n" ); document.write( "m = 390/13
\n" ); document.write( "m = 30 yrs is Mom's age
\n" ); document.write( "then
\n" ); document.write( "b = $\"1%2F6\"$ *30
\n" ); document.write( "b = 5 yrs is Beth's age
\n" ); document.write( "and
\n" ); document.write( "d = 30 + 7
\n" ); document.write( "d = 37 yrs is Dad's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this, find the total
\n" ); document.write( "5 + 30 + 37 = 72\r
\n" ); document.write( "
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