document.write( "Question 620590: Graph the quadratic equation by plotting points.\r
\n" ); document.write( "\n" ); document.write( "y=(x-3)^2\r
\n" ); document.write( "\n" ); document.write( "please include what points to plot. Thanks
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Algebra.Com's Answer #390292 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The function is in vertex form, so read the coordinates of the vertex directly and plot that. Coincidentally, the vertex is on the x-axis in this case, so you have your x-intercept also. If you don't know how to interpret the vertex form, Google \"vertex form of a parabola\" and pick the first thing that comes up.\r
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\n" ); document.write( "\n" ); document.write( "Then substitute 0 for x and calculate the y-coordinate of the y-intercept. Plot that.\r
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\n" ); document.write( "\n" ); document.write( "Figure out how far along the x-axis it is from the origin to the vertex, then go that same distance on the other side of the vertex to find a point with the same y-value as the y-intercept (symmetry)\r
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\n" ); document.write( "\n" ); document.write( "Pick any other x-value (different from 0, the x-coordinate of the vertex, and the x-coordinate of the point symmetrical to the y-intercept) and calculate the value of the function for that x-value. Then use symmetry again to find a symmetrical point on the other side of the vertex.\r
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\n" ); document.write( "\n" ); document.write( "That gives you 5 points which should be enough.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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