document.write( "Question 620599: Minh walked a total of 4 miles in 75 minutes. It he walked at 3.5 miles per hour for the first 30 minutes, what was his average speed for the rest of the time? \n" ); document.write( "
Algebra.Com's Answer #390286 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Minh walked a total of 4 miles in 75 minutes. \n" ); document.write( " If he walked at 3.5 miles per hour for the first 30 minutes, what was his average speed for the rest of the time? \n" ); document.write( ": \n" ); document.write( "Convert 75 min to 1.25 hrs. and 30 min to .5 hrs \n" ); document.write( ": \n" ); document.write( "Let s = his speed the the last half mile \n" ); document.write( "and \n" ); document.write( "1.25 - .5 = .75 hrs = \"the rest of the time\" \n" ); document.write( ": \n" ); document.write( "Write a dist equation: dist = speed * time \n" ); document.write( ": \n" ); document.write( "3.5(.5) + .75s = 4 \n" ); document.write( "1.75 + .75s = 4 \n" ); document.write( ".75s = 4 - 1.75 \n" ); document.write( ".75s = 2.25 \n" ); document.write( "s = 2.25/.75 \n" ); document.write( "s = 3 mph his speed the last half mile \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the total distance \n" ); document.write( "3.5 * .5 = 1.75 mi \n" ); document.write( "3.0 * .75 = 2.25 \n" ); document.write( "----------------- \n" ); document.write( "total dist 4 mi \n" ); document.write( " \n" ); document.write( " |