document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620557>Question 620557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Recall that for triangle ABC the law of sines states that (sin A)/a= (sin B)/b= (sin C)/c. If angle A= 30, angle B= 45, and a= 16, find b. \r<BR>\n" );
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document.write( "A. Square root of 2 <BR>\n" );
document.write( "B. 4 times the square root of 2 <BR>\n" );
document.write( "C. the square root of 2 divided by 32 <BR>\n" );
document.write( "D. 16 times the square root of 2 \r<BR>\n" );
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document.write( "I know the answer is D. but i do not know how to reach that solution.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390224 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (sin A)/a= (sin B)/b\r<BR>\n" );
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document.write( "(sin(30))/16 = (sin(45))/b\r<BR>\n" );
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document.write( "(1/2)/16 = (sqrt(2)/2)/b\r<BR>\n" );
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document.write( "(1/2)*b = 16*sqrt(2)/2\r<BR>\n" );
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document.write( "b/2 = 8*sqrt(2)\r<BR>\n" );
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document.write( "b = 2*8*sqrt(2)\r<BR>\n" );
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document.write( "b = <font color=\"red\">16*sqrt(2)</font> </SPAN>\n" );
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