document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620556>Question 620556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a perimeter of 34in and has an area of 60 in. What is the length of the diagnol of the rectangle? <BR>\n" );
document.write( "A. 12 in. <BR>\n" );
document.write( "B. 13 in. <BR>\n" );
document.write( "C. 15 in. \r<BR>\n" );
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document.write( "I know the answer is B. 13 in. however I do not know how to reach that answer \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390223 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is 34, so 34 = 2L+2W or L+W = 17. Solve for L to get L = 17-W\r<BR>\n" );
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document.write( "The area is 60, so 60 = LW. Plug in L = 17-W to get\r<BR>\n" );
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document.write( "60 = (17-W)W\r<BR>\n" );
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document.write( "Now solve for W. Then use this solution for W to find L.\r<BR>\n" );
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document.write( "Once you have L and W. Plug them into the formula\r<BR>\n" );
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document.write( "D = sqrt( L^2 + W^2 )\r<BR>\n" );
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document.write( "to find the length of the diagonal D </SPAN>\n" );
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