document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=7120>Question 7120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ( Evaluate each expression for the given values of the variables)\r<BR>\n" );
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document.write( "3(2c+d)-d; c=5 and d=1<BR>\n" );
document.write( "3(2+5+1)-d\r<BR>\n" );
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document.write( "I dont understand the second step if i do what is in the parenthese first then distrubute or distrubute first? i just cant get past the second step. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3902 by </B><A HREF=/tutors/aboutme.mpl?userid=glabow><B>glabow(165)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=glabow><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I don't undrstand your substitution of c=5 and d=1.<BR>\n" );
document.write( "The expression<BR>\n" );
document.write( "3(2c+d)-d says to multiply c by 2, then add d. This entire group is then multiplied by 3 and at the very last d is subtracted.<BR>\n" );
document.write( "So,<BR>\n" );
document.write( "3 ( 2x5 + 1) - 1 = 3 ( 10 + 1) - 1 = 3(11) - 1 = 33 - 1 = 32<BR>\n" );
document.write( "Rule is:<BR>\n" );
document.write( "Do the operations in all groups first<BR>\n" );
document.write( "Do multiplication and division before addition and subtraction.<BR>\n" );
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