document.write( "Question 620474: i need help with this two part question we started slope and i am lost and getting frustrated. can someone help me step by step explain what you did. \r
\n" ); document.write( "\n" ); document.write( "1.The distance of the point (1,5) from the line y = -2 x - 1
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\n" ); document.write( "\n" ); document.write( "2.The equation of the line that goes through the point ( 4 ,6 ) and is perpendicular to the line 4 x + 2 y = 3 can be written in the form y = mx+b where m is and b is \r
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Algebra.Com's Answer #390175 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "There is also a formula for your first problem:\r\n" );
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document.write( "The distance from the point \r\n" );
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document.write( "(x1,y1) to the line whose equation is Ax + By + C = 0 \r\n" );
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document.write( "is given by the formula:\r\n" );
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document.write( "d = \"%28Ax%5B1%5D%2BBy%5B1%5D%2BC%29%2Fsqrt%28A%5E2%2BB%5E2%29\"\r\n" );
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document.write( "Your equation is \r\n" );
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document.write( "y = -2x - 1\r\n" );
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document.write( "which is equivalent to\r\n" );
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document.write( "2x + y + 1 = 0\r\n" );
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document.write( "Compare that to\r\n" );
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document.write( "Ax + By + C = 0\r\n" );
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document.write( "and A=2, B=1, and C=1,  (x1,y1) = (1,5) \r\n" );
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document.write( "Substitute in\r\n" );
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document.write( "d = \"%28Ax%5B1%5D%2BBy%5B1%5D%2BC%29%2Fsqrt%28A%5E2%2BB%5E2%29\"\r\n" );
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document.write( "d = \"%28%282%29%281%29%2B%281%29%285%29%2B1%29%2Fsqrt%282%5E2%2B1%5E2%29\"\r\n" );
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document.write( "d = \"%282%2B5%2B1%29%2Fsqrt%284%2B1%29\"\r\n" );
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document.write( "d = \"8%2Fsqrt%285%29\"\r\n" );
document.write( "d = \"8%2Fsqrt%285%29\"·\"sqrt%285%29%2Fsqrt%285%29\"\r\n" );
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document.write( "d = \"8sqrt%285%29%2F5\" which is approximately 3.5777, as the other tutor found.\r\n" );
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document.write( "Edwin
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