document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620402>Question 620402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One of the complimentary angle measure 15° increased by half its compliment. Find the measure of both angles. Please answer my question quickly. Reply ASAP. Thanks in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390105 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One of the complimentary angle measure 15° increased by half its compliment.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "90-x = complement of angle<BR>\n" );
document.write( ".<BR>\n" );
document.write( "from: \"One of the complimentary angle measure 15° increased by half its compliment\" we have:<BR>\n" );
document.write( "x = 15+(90-x)/2<BR>\n" );
document.write( "multiplying both sides by 2:<BR>\n" );
document.write( "2x = 30+(90-x)<BR>\n" );
document.write( "2x = 30+90-x<BR>\n" );
document.write( "3x = 30+90<BR>\n" );
document.write( "3x = 120<BR>\n" );
document.write( "x = 40 degrees<BR>\n" );
document.write( ".<BR>\n" );
document.write( "complement:<BR>\n" );
document.write( "90-x = 90-40 = 50 degrees<BR>\n" );
document.write( ".<BR>\n" );
document.write( "answer:<BR>\n" );
document.write( "the two angles are 40 and 50 degrees\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );