document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620398>Question 620398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular sign is not to exceed 50 feet. The length is to be twice the width. What widths will meet these conditions?\r<BR>\n" );
document.write( "\n" );
document.write( "The only formula I know is: P=2(l+w)  I dont understand how this formula solves this problem.....please help me. Your time and efforts will be greatly appreciated. Thank You. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390099 by </B><A HREF=/tutors/aboutme.mpl?userid=kingme18><B>kingme18(98)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kingme18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kingme18><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390099\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the length is to be twice the width, you can say l = 2w (length equals two times width).  That means that l is the same as 2w...so in your formula, instead of l, you can say 2w:  P = 2(2w + w)\r<BR>\n" );
document.write( "\n" );
document.write( "Since perimeter is 50 ft, plug that in for P and solve:\r<BR>\n" );
document.write( "\n" );
document.write( "50=2(2w+w)<BR>\n" );
document.write( "50=2(3w)<BR>\n" );
document.write( "50=6w<BR>\n" );
document.write( "8.333...=w\r<BR>\n" );
document.write( "\n" );
document.write( "w is 8.333... and l is twice that, or 16.666...\r<BR>\n" );
document.write( "\n" );
document.write( "Since this is in terms of feet, we can write 8.333... ft as 8 ft, 4 inches (because .333... is 1/3, and 1/3 of a foot is 4 inches) and 16.666... ft as 16 ft, 8 inches. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );