document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620284>Question 620284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have one angle that measures 45 degrees less than twice the measure of its supplement, what is the measure of<BR>\n" );
document.write( "each angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #390050 by </B><A HREF=/tutors/aboutme.mpl?userid=MsRedz123><B>MsRedz123(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MsRedz123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MsRedz123><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=390050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the measure of the angle<BR>\n" );
document.write( "Let y be the supplement.\r<BR>\n" );
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document.write( "x=2y-45\r<BR>\n" );
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document.write( "x + y = 180<BR>\n" );
document.write( "(2y-45) + y = 180<BR>\n" );
document.write( "3y = 225<BR>\n" );
document.write( "3y/3 = 225/3<BR>\n" );
document.write( "y=75\r<BR>\n" );
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document.write( "Then, find x using the measure of y.\r<BR>\n" );
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document.write( "x + y = 180<BR>\n" );
document.write( "x + 75 = 180<BR>\n" );
document.write( "x = 105\r<BR>\n" );
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document.write( "or x = 2y-45<BR>\n" );
document.write( "x=2(75)-45<BR>\n" );
document.write( "x=150-45<BR>\n" );
document.write( "x=105\r<BR>\n" );
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document.write( "Therefore, the measure of the angle is 105 degrees and its supplement measures 75 degrees.    </SPAN>\n" );
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