document.write( "Question 620029: the ratio of income of A to that B is 5:4 and the expenditure of A to that of B is 3:2 if at end of the year each saves 800 the income of A is ? \n" ); document.write( "
Algebra.Com's Answer #390040 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the ratio of income of A to that B is 5:4 \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "5B = 4A \n" ); document.write( "B = \n" ); document.write( "B = .8A \n" ); document.write( ": \n" ); document.write( "and the expenditure of A to that of B is 3:2 \n" ); document.write( ": \n" ); document.write( "at then end of the year each saves 800, \n" ); document.write( ": \n" ); document.write( "therefore we can say \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "2(A-800) = 3(B-800) \n" ); document.write( "2A - 1600 = 3B - 2400 \n" ); document.write( "2A = 3B - 2400 + 1600 \n" ); document.write( "2A = 3B - 800 \n" ); document.write( "replace b with .8A \n" ); document.write( "2A = 3(.8A) - 800 \n" ); document.write( "2A = 2.4A - 800 \n" ); document.write( "2A - 2.4a = -800 \n" ); document.write( "-.4A = -800 \n" ); document.write( "A = \n" ); document.write( "A = $2000 is A's income\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |