document.write( "Question 620029: the ratio of income of A to that B is 5:4 and the expenditure of A to that of B is 3:2 if at end of the year each saves 800 the income of A is ? \n" ); document.write( "
Algebra.Com's Answer #390040 by ankor@dixie-net.com(22740)\"\" \"About 
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the ratio of income of A to that B is 5:4
\n" ); document.write( "\"A%2FB\" = \"5%2F4\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "5B = 4A
\n" ); document.write( "B = \"4%2F5\"A
\n" ); document.write( "B = .8A
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\n" ); document.write( "and the expenditure of A to that of B is 3:2
\n" ); document.write( ":
\n" ); document.write( "at then end of the year each saves 800,
\n" ); document.write( ":
\n" ); document.write( "therefore we can say
\n" ); document.write( "\"%28%28A-800%29%29%2F%28%28B-800%29%29\" = \"3%2F2\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "2(A-800) = 3(B-800)
\n" ); document.write( "2A - 1600 = 3B - 2400
\n" ); document.write( "2A = 3B - 2400 + 1600
\n" ); document.write( "2A = 3B - 800
\n" ); document.write( "replace b with .8A
\n" ); document.write( "2A = 3(.8A) - 800
\n" ); document.write( "2A = 2.4A - 800
\n" ); document.write( "2A - 2.4a = -800
\n" ); document.write( "-.4A = -800
\n" ); document.write( "A = \"%28-800%29%2F%28-.4%29\"
\n" ); document.write( "A = $2000 is A's income\r
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