document.write( "Question 620108: a rectangle with a perimeter of 102 inches is half as wide as it is long determine the length of this rectangle in inches \n" ); document.write( "
Algebra.Com's Answer #390028 by math-vortex(648)![]() ![]() You can put this solution on YOUR website! Hi, there-- \n" ); document.write( ". \n" ); document.write( "STEP I: Choose variables \n" ); document.write( ". \n" ); document.write( "Let W be the width of the rectangle. \n" ); document.write( "Let L be the length. \n" ); document.write( ". \n" ); document.write( "STEP II: Write equations to model the situation. \n" ); document.write( ". \n" ); document.write( "The formula for the perimeter of a rectangle is P = 2W+2L, so \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "In algebra, \"half as wide as it is long\" can be written as \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Note: It's easy to confuse the words with the algebra. Once you have your equation test it with a few values. For example, \"3 is half as wide as 6, and 3=(1/2)*6. \n" ); document.write( ". \n" ); document.write( "STEP III: Solve your system of equations. \n" ); document.write( "Substitute(1/2)*L for W in the first equation. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Simplify. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The length of the rectangle is 34 inches. \n" ); document.write( ". \n" ); document.write( "STEP IV: Check your work. \n" ); document.write( "Since the rectangle is half as wide as it is long, the width must be 17. Thus the perimeter is 2(17)+2(34)=34+68=102. Check! \n" ); document.write( ". \n" ); document.write( "Hope this helps. Feel free to email if you still have questions about this. \n" ); document.write( ". \n" ); document.write( "Ms.Figgy \n" ); document.write( "math.in.the.vortex@gmail.com \n" ); document.write( " |