document.write( "Question 620108: a rectangle with a perimeter of 102 inches is half as wide as it is long determine the length of this rectangle in inches \n" ); document.write( "
Algebra.Com's Answer #390028 by math-vortex(648)\"\" \"About 
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Hi, there--
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\n" ); document.write( "STEP I: Choose variables
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\n" ); document.write( "Let W be the width of the rectangle.
\n" ); document.write( "Let L be the length.
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\n" ); document.write( "STEP II: Write equations to model the situation.
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\n" ); document.write( "The formula for the perimeter of a rectangle is P = 2W+2L, so
\n" ); document.write( "\"102=2W%2B2L\"
\n" ); document.write( "\"51=W%2BL\"
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\n" ); document.write( "In algebra, \"half as wide as it is long\" can be written as
\n" ); document.write( "\"W=%281%2F2%29%2AL\"
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\n" ); document.write( "Note: It's easy to confuse the words with the algebra. Once you have your equation test it with a few values. For example, \"3 is half as wide as 6, and 3=(1/2)*6.
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\n" ); document.write( "STEP III: Solve your system of equations.
\n" ); document.write( "Substitute(1/2)*L for W in the first equation.
\n" ); document.write( "\"51=W%2BL\"
\n" ); document.write( "\"51+=+%281%2F2%29%2AL%2BL\"
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\n" ); document.write( "Simplify.
\n" ); document.write( "\"51=%283%2F2%29L\"
\n" ); document.write( "\"L=%282%2F3%29%2851%29=34\"
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\n" ); document.write( "The length of the rectangle is 34 inches.
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\n" ); document.write( "STEP IV: Check your work.
\n" ); document.write( "Since the rectangle is half as wide as it is long, the width must be 17. Thus the perimeter is 2(17)+2(34)=34+68=102. Check!
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\n" ); document.write( "Hope this helps. Feel free to email if you still have questions about this.
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\n" ); document.write( "Ms.Figgy
\n" ); document.write( "math.in.the.vortex@gmail.com
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