document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620155>Question 620155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 64x^2+16y^2+320x-192y+960=0<BR>\n" );
document.write( "need in ellipse form plus foci, verts, and ecc\r<BR>\n" );
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document.write( "I got for the formula 4(x+5/2)^2 + (y-6)^2 =1 not sure if this is right<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389995 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 64x^2+16y^2+320x-192y+960=0<BR>\n" );
document.write( "need in ellipse form plus foci, verts, and ecc <BR>\n" );
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document.write( "64x^2+16y^2+320x-192y+960=0<BR>\n" );
document.write( "complete the square<BR>\n" );
document.write( "64x^2+320x+16y^2-192y+960=0<BR>\n" );
document.write( "64(x^2+5+25/4)+16(y^2-12y+36)=-960+400+576<BR>\n" );
document.write( "64(x+5/2)^2+16(y-6)^2=16<BR>\n" );
document.write( "(x+5/2)^2/(16/64)+(y-6)^2=1<BR>\n" );
document.write( "(x+5/2)^2/(1/4)+(y-6)^2=1<BR>\n" );
document.write( "This is an equation of ellipse with vertical major axis.<BR>\n" );
document.write( "Its standard form: (x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k)=(x,y) coordinates of center<BR>\n" );
document.write( "For given equation:<BR>\n" );
document.write( "center:(-5/2,6)<BR>\n" );
document.write( "a^2=1<BR>\n" );
document.write( "a=1<BR>\n" );
document.write( "vertices: (-5/2,6±a)=(-5/2, 6±1)= (-5/2,5) and (-5/2,7)<BR>\n" );
document.write( "b^2=1/4<BR>\n" );
document.write( "b=&#8730;(1/4)=1/2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "c^2=a^2-b^2=1-1/4=3/4<BR>\n" );
document.write( "c=&#8730;(3/4)&#8776;.87<BR>\n" );
document.write( "foci: (-5/2,6±c)=(-5/2, 6±.87)= (-5/2,5.13) and (-5/2,6.87)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "eccentricity: c/a=c/1&#8776;.87\r<BR>\n" );
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