document.write( "Question 620146: My price is $64,413.02, which is 45.9% higher than my competitor's price. What is my competitor's price? \n" ); document.write( "
Algebra.Com's Answer #389982 by fcabanski(1391)\"\" \"About 
You can put this solution on YOUR website!
Call the competitor's price x. When a price is y% higher it's x(1+y%).

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\n" ); document.write( "\n" ); document.write( "64,413.02 = x(1+.459)


\n" ); document.write( "64,413.02 = 1.459x


\n" ); document.write( "44148.75=x, the competitor's price.
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Hope the solution helped. Sometimes you need more than a solution. Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)
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