document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620192>Question 620192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of an 80% antifreeze solution must be mixed with 100 gallons of 30% antifreeze to get a mixture that is 70% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389974 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for a concentrated mixture is <P>\r<BR>\n" );
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document.write( "% times gallons (1) + % times gallons (2) / gallons (1+2) = New mixture %.<P>\r<BR>\n" );
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document.write( ".8x + 30 = 70 + .7x<P><BR>\n" );
document.write( ".1x = 40<P><BR>\n" );
document.write( "x = 400<BR>\n" );
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